1. A sample of $10.0\text{ g}$ of a hydrate of barium chloride ($BaCl_2 \cdot xH_2O$) is heated until all the water of crystallization is removed. The residue of anhydrous barium chloride weighs $8.525\text{ g}$. What is the value of $x$? (Atomic masses: $Ba = 137, Cl = 35.5, H = 1, O = 16$)
A) 1
B) 3
C) 2
D) 4
Correct Answer: C
Mass of water lost = $10.0 - 8.525 = 1.475\text{ g}$.<br>Moles of $BaCl_2 = \frac{8.525}{137 + (2 \times 35.5)} = \frac{8.525}{208} \approx 0.041\text{ mol}$.<br>Moles of $H_2O = \frac{1.475}{18} \approx 0.082\text{ mol}$.<br>Ratio $x = \frac{n(H_2O)}{n(BaCl_2)} = \frac{0.082}{0.041} = 2$.<br>Correct Answer: 2


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