1. A sample of 10.0 g of a hydrate of barium chloride ($BaCl_2 \cdot xH_2O$) is heated until all the water of crystallization is removed. The residue of anhydrous barium chloride weighs 8.525 g. What is the value of x? (Atomic masses: Ba = 137, Cl = 35.5, H = 1, O = 16)
A) 1B) 3C) 2D) 4
✓ Correct Answer: Option C
Explanation: Mass of water lost = 10.0 - 8.525 = 1.475g.<br>Moles of $BaCl_2 = \frac{8.525}{137 + (2 \times 35.5)} = \frac{8.525}{208} \approx 0.041 mol$.<br>Moles of $H_2O = \frac{1.475}{18} \approx 0.082 mol$.<br>Ratio $x = \frac{n(H_2O)}{n(BaCl_2)} = \frac{0.082}{0.041} = 2$.<br>Correct Answer: 2