1. If $x + \frac{1}{x} = 4$, find the value of $x^2 + \frac{1}{x^2}$.
A) 14B) 16C) 18D) 20
✓ Correct Answer: Option A
Explanation: <b>Solution:</b><br>
Given $x + \frac{1}{x} = 4$. Square both sides:<br>
$(x + \frac{1}{x})^2 = 4^2$<br>
$x^2 + 2(x)(\frac{1}{x}) + \frac{1}{x^2} = 16$<br>
$x^2 + 2 + \frac{1}{x^2} = 16 ⇒ x^2 + \frac{1}{x^2} = 16 - 2 = 14$.