1. A technician uses a micrometer screw gauge with a least count of 0.01 mm to measure the diameter of a thin copper wire. The main scale reading is 2.5 mm and the $34^{th}$ division of the circular scale coincides with the reference line. If the zero error is -0.03 mm, what is the correct diameter of the wire?
A) 2.84 mmB) 2.81 mmC) 2.87 mmD) 2.53 mm
✓ Correct Answer: Option C
Explanation: <b>Solution:</b><br> Measured Reading = $MSR + (VSR \times LC)$ <br> Measured Reading = $2.5 mm + (34 \times 0.01 mm) = 2.5 + 0.34 = 2.84 mm$. <br> Correct Reading = Measured Reading - Zero Error <br> Correct Reading = 2.84 - (-0.03) = 2.84 + 0.03 = 2.87 mm.