1. In an experimental plot of <i>Oryza sativa</i>, a researcher aims to produce exactly 600 viable seeds. What is the minimum number of meiotic divisions required to achieve this?
A) 600B) 150C) 750D) 1200
✓ Correct Answer: Option C
Explanation: To produce n seeds: <br>1. n pollen grains are needed. Since 1 meiosis \rightarrow 4 pollen grains, we need n/4 divisions. <br>2. n ovules (embryo sacs) are needed. Since 1 meiosis \rightarrow 1 functional megaspore, we need n divisions. <br>Total = $n + \frac{n}{4} = 600 + \frac{600}{4} = 600 + 150 = 750$.