1. Evaluate the following expression carefully: $1.25 \times 0.08 \times 10.5$

$1.05$

$10.5$

$0.105$

$1.50$

Solution:
Step 1: Multiply $1.25$ and $0.08$.
$125 \times 8 = 1000$. With 4 decimal places, $1.25 \times 0.08 = 0.1$.
Step 2: Multiply the result by $10.5$.
$0.1 \times 10.5 = 1.05$.

2. A rectangular hall has an area of $48.96 \text{ m}^2$. If the breadth of the hall is $5.1 \text{ m}$, find the perimeter of the hall.

$14.7 \text{ m}$

$29.4 \text{ m}$

$24.48 \text{ m}$

$19.2 \text{ m}$

Solution:
$\text{Length} = \text{Area} \div \text{Breadth} = 48.96 \div 5.1 = 9.6 \text{ m}$.
$\text{Perimeter} = 2(\text{Length} + \text{Breadth}) = 2(9.6 + 5.1) = 2(14.7) = 29.4 \text{ m}$.

3. If $234 \times 56 = 13104$, what is the value of $13.104 \div 0.056$?

$2.34$

$23.4$

$234$

$2340$

Solution:
Given $234 \times 56 = 13104$, then $\frac{13104}{56} = 234$.
$13.104 \div 0.056 = \frac{13.104}{0.056}$.
Multiply both parts by $1000$: $\frac{13104}{56} = 234$.

4. A metal rod of length $15.75 \text{ m}$ is cut into $25$ equal small pieces. What is the length of each piece in centimeters?

$0.63 \text{ cm}$

$6.3 \text{ cm}$

$630 \text{ cm}$

$63 \text{ cm}$

Solution:
Length in meters $= 15.75 \div 25 = 0.63 \text{ m}$.
To convert to cm: $0.63 \times 100 = 63 \text{ cm}$.

5. Express the sum of $3 \frac{7}{125}$ and $2 \frac{4}{25}$ as a decimal.

$5.216$

$5.116$

$5.056$

$5.28$

Solution:
$3 \frac{7}{125} = 3 + \frac{56}{1000} = 3.056$.
$2 \frac{4}{25} = 2 + \frac{16}{100} = 2.16$.
$\text{Sum} = 3.056 + 2.160 = 5.216$.

6. A car travels $16.5 \text{ km}$ using $1$ litre of petrol. How many litres of petrol will be required to cover a distance of $338.25 \text{ km}$?

$2.05 \text{ litres}$

$25 \text{ litres}$

$20.5 \text{ litres}$

$21.5 \text{ litres}$

Solution:
$\text{Petrol required} = 338.25 \div 16.5 = 20.5 \text{ litres}$.

7. What must be added to the product of $0.12$ and $0.5$ to get $1$?

$0.88$

$0.94$

$0.06$

$0.96$

Solution:
$\text{Product} = 0.12 \times 0.5 = 0.06$.
$x + 0.06 = 1 \implies x = 1 - 0.06 = 0.94$.

8. Solve: $(0.2)^3 + (0.3)^2 - 0.05$

$0.013$

$0.14$

$0.098$

$0.048$

Solution:
$(0.2)^3 = 0.008$.
$(0.3)^2 = 0.09$.
$0.008 + 0.09 - 0.05 = 0.098 - 0.05 = 0.048$.

9. A vessel contains $4.5$ litres of milk. If $0.75$ litres of milk is poured into each of several small bottles, how many bottles are filled?

$5$

$8$

$6$

$60$

Solution:
$\text{Number of bottles} = 4.5 \div 0.75 = 450 \div 75 = 6$.

10. Which of the following is equal to $0.007 \times 10^3 + 0.7 \div 10^2$?

$7.007$

$0.707$

$70.07$

$7.07$

Solution:
$0.007 \times 1000 = 7$.
$0.7 \div 100 = 0.007$.
$\text{Sum} = 7 + 0.007 = 7.007$.

Grade 7 Maths Quiz - A Peek Beyond the Point (Set 2) | Concept of Maths

Grade 7 : Mathematics (Ganita Prakash) - 3. A Peek Beyond the Point (Set 2) | Concept of Maths

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