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Complete Syllabus Question Paper
Grade 11 : Chemistry - Chemical Bonding (Set 3)— Questions & Detailed Solutions
Q1
Structure of Ozone ($O_3$): Central Oxygen atom ($O_B$) forms a double bond with one terminal oxygen ($O_A$) and a single coordinate bond with the other terminal oxygen ($O_C$).
What is the formal charge on the central oxygen atom ($O_B$) in the ozone ($O_3$) molecule?
(A)
0
(B)
+1
(C)
-1
(D)
+2
Q2
According to VSEPR theory, what is the molecular geometry of sulfur tetrafluoride ($SF_4$)?
According to VSEPR theory, what is the molecular geometry of sulfur tetrafluoride ($SF_4$)?
(A)
Tetrahedral
(B)
Square planar
(C)
See-saw
(D)
Trigonal bipyramidal
Q3
Compound Cation Radii (pm) Cation Charge LiCl 76 +1 NaCl 102 +1 KCl 138 +1 RbCl 152 +1
Based on Fajan's rules and the data above, which alkali metal chloride possesses the highest covalent character?
| Compound | Cation Radii (pm) | Cation Charge |
|---|---|---|
| LiCl | 76 | +1 |
| NaCl | 102 | +1 |
| KCl | 138 | +1 |
| RbCl | 152 | +1 |
Based on Fajan's rules and the data above, which alkali metal chloride possesses the highest covalent character?
(A)
RbCl
(B)
KCl
(C)
NaCl
(D)
LiCl
Q4
What is the hybridization of the central atom and the shape of the xenon tetrafluoride ($XeF_4$) molecule?
What is the hybridization of the central atom and the shape of the xenon tetrafluoride ($XeF_4$) molecule?
(A)
$sp^3d$, Trigonal bipyramidal
(B)
$sp^3d^2$, Square planar
(C)
$sp^3d^2$, Octahedral
(D)
$sp^3$, Tetrahedral
Q5
Using Molecular Orbital Theory, determine the bond order of the dioxygen cation ($O_2^+$).
Using Molecular Orbital Theory, determine the bond order of the dioxygen cation ($O_2^+$).
(A)
1.5
(B)
2.0
(C)
2.5
(D)
3.0
Q6
Statement I: Ammonia ($NH_3$) has a net dipole moment of 1.47 D.
Statement II: Nitrogen trifluoride ($NF_3$) has a net dipole moment of 0.23 D.
Which statement correctly explains why the dipole moment of $NH_3$ is significantly greater than that of $NF_3$?
Statement I: Ammonia ($NH_3$) has a net dipole moment of 1.47 D.
Statement II: Nitrogen trifluoride ($NF_3$) has a net dipole moment of 0.23 D.
Which statement correctly explains why the dipole moment of $NH_3$ is significantly greater than that of $NF_3$?
(A)
In $NH_3$, the lone pair dipole opposes the N-H bond dipoles.
(B)
In $NF_3$, the lone pair dipole opposes the resultant vector of N-F bond dipoles.
(C)
Nitrogen is more electronegative than fluorine.
(D)
$NF_3$ has a planar structure while $NH_3$ is pyramidal.
Q7
Consider the molecule vinylacetylene: $HC \equiv C - CH = CH_2$.Calculate the total number of sigma ($\sigma$) and pi ($\pi$) bonds present in one molecule of vinylacetylene.
Consider the molecule vinylacetylene: $HC \equiv C - CH = CH_2$.
Calculate the total number of sigma ($\sigma$) and pi ($\pi$) bonds present in one molecule of vinylacetylene.
(A)
$6\sigma, 3\pi$
(B)
$7\sigma, 3\pi$
(C)
$7\sigma, 2\pi$
(D)
$8\sigma, 3\pi$
Q8
Which of the following compounds exhibits intramolecular hydrogen bonding, making it steam-volatile with a lower boiling point?
Which of the following compounds exhibits intramolecular hydrogen bonding, making it steam-volatile with a lower boiling point?
(A)
p-Nitrophenol
(B)
o-Nitrophenol
(C)
Methanol
(D)
Water
Q9
Which of the following choices correctly represents the decreasing order of H-M-H bond angle among Group 15 hydrides?
Which of the following choices correctly represents the decreasing order of H-M-H bond angle among Group 15 hydrides?
(A)
$NH_3 > PH_3 > AsH_3 > SbH_3$
(B)
$SbH_3 > AsH_3 > PH_3 > NH_3$
(C)
$PH_3 > NH_3 > AsH_3 > SbH_3$
(D)
$NH_3 > AsH_3 > PH_3 > SbH_3$
Q10
According to Molecular Orbital Theory, which of the following homonuclear diatomic molecules contains TWO unpaired electrons in its ground state?
According to Molecular Orbital Theory, which of the following homonuclear diatomic molecules contains TWO unpaired electrons in its ground state?
(A)
$N_2$
(B)
$C_2$
(C)
$B_2$
(D)
$Li_2$
Q11
What is the formal C-O bond order in the carbonate ion ($CO_3^{2-}$)?
What is the formal C-O bond order in the carbonate ion ($CO_3^{2-}$)?
(A)
1.0
(B)
1.33
(C)
1.5
(D)
2.0
Q12
In solid state, phosphorus pentachloride exists as $[PCl_4]^+[PCl_6]^-$. What is the hybridization of the phosphorus atom in the cationic species $[PCl_4]^+$?
In solid state, phosphorus pentachloride exists as $[PCl_4]^+[PCl_6]^-$. What is the hybridization of the phosphorus atom in the cationic species $[PCl_4]^+$?
(A)
$sp^3d$
(B)
$sp^3d^2$
(C)
$sp^3$
(D)
$sp^2$
Q13
Ionic Compound Cation Charge Anion Charge NaCl +1 -1 NaF +1 -1 MgO +2 -2 AlN +3 -3
Based on charge product and ion size principles, which compound possesses the HIGHEST lattice energy?
| Ionic Compound | Cation Charge | Anion Charge |
|---|---|---|
| NaCl | +1 | -1 |
| NaF | +1 | -1 |
| MgO | +2 | -2 |
| AlN | +3 | -3 |
Based on charge product and ion size principles, which compound possesses the HIGHEST lattice energy?
(A)
NaCl
(B)
MgO
(C)
AlN
(D)
NaF
Q14
Approaching orbitals along the x-axis: A spherical $s$ orbital approaches a dumbbell $p_y$ orbital oriented perpendicular to the x-axis.Which pair of atomic orbitals results in ZERO net overlap (non-bonding) when approaching along the x-axis?
Approaching orbitals along the x-axis: A spherical $s$ orbital approaches a dumbbell $p_y$ orbital oriented perpendicular to the x-axis.
Which pair of atomic orbitals results in ZERO net overlap (non-bonding) when approaching along the x-axis?
(A)
$s$ and $p_x$
(B)
$p_y$ and $p_y$
(C)
$s$ and $p_y$
(D)
$p_x$ and $p_x$
Q15
Which pair among the following consists of ISOSTRUCTURAL species (same molecular geometry)?
Which pair among the following consists of ISOSTRUCTURAL species (same molecular geometry)?
(A)
$CO_2$ and $SO_2$
(B)
$NH_3$ and $H_3O^+$
(C)
$ClF_3$ and $BF_3$
(D)
$XeF_4$ and $SF_4$
Q16
Comparing $N_2^+$ and $N_2^-$, which species is MORE stable and why?
Comparing $N_2^+$ and $N_2^-$, which species is MORE stable and why?
(A)
$N_2^-$ because it has more total electrons.
(B)
$N_2^+$ because it has fewer electrons in antibonding orbitals.
(C)
Both have identical stability because both have a bond order of 2.5.
(D)
$N_2^-$ because it has a higher bond order.
Q17
The experimental dipole moment of HCl is 1.03 D. The internuclear distance between $H$ and Cl is 1.275 \AA ($1\text{ D} = 3.336 \times 10^{-30}\text{ C m}$, $e = 1.602 \times 10^{-19}\text{ C}$).What is the percentage ionic character of the $H-Cl$ bond?
The experimental dipole moment of HCl is 1.03 D. The internuclear distance between $H$ and Cl is 1.275 \AA ($1\text{ D} = 3.336 \times 10^{-30}\text{ C m}$, $e = 1.602 \times 10^{-19}\text{ C}$).
What is the percentage ionic character of the $H-Cl$ bond?
(A)
16.8%
(B)
33.5%
(C)
50.0%
(D)
83.2%
Q18
What is the molecular shape and the number of lone pairs on the central Xe atom in xenon difluoride ($XeF_2$)?
What is the molecular shape and the number of lone pairs on the central Xe atom in xenon difluoride ($XeF_2$)?
(A)
Bent, 2 lone pairs
(B)
Linear, 3 lone pairs
(C)
Linear, 2 lone pairs
(D)
Trigonal planar, 3 lone pairs
Q19
Structure of propadiene (allene): $H_2C^{(1)} = C^{(2)} = C^{(3)}H_2$.What are the hybridization states of carbon atoms 1, 2, and 3 from left to right in propadiene?
Structure of propadiene (allene): $H_2C^{(1)} = C^{(2)} = C^{(3)}H_2$.
What are the hybridization states of carbon atoms 1, 2, and 3 from left to right in propadiene?
(A)
$sp^2, sp^2, sp^2$
(B)
$sp^3, sp, sp^3$
(C)
$sp^2, sp, sp^2$
(D)
$sp, sp^2, sp$
Q20
Molecule Hybridization Lone Pairs Bond Angle $CH_4$ $sp^3$ 0 $109.5^\circ$ $NH_3$ $sp^3$ 1 $107.0^\circ$ $H_2O$ $sp^3$ 2 $104.5^\circ$
Based on VSEPR theory and the table above, why does $H_2O$ have a smaller bond angle than $NH_3$?
| Molecule | Hybridization | Lone Pairs | Bond Angle |
|---|---|---|---|
| $CH_4$ | $sp^3$ | 0 | $109.5^\circ$ |
| $NH_3$ | $sp^3$ | 1 | $107.0^\circ$ |
| $H_2O$ | $sp^3$ | 2 | $104.5^\circ$ |
Based on VSEPR theory and the table above, why does $H_2O$ have a smaller bond angle than $NH_3$?
(A)
$H_2O$ experiences lone pair-lone pair repulsion which is stronger than lone pair-bond pair repulsion in $NH_3$.
(B)
Oxygen is less electronegative than nitrogen.
(C)
$NH_3$ has more lone pairs than $H_2O$.
(D)
$H_2O$ is non-polar whereas $NH_3$ is polar.

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